Webb7 okt. 2024 · The probability that they all miss is (1/2) (1/3) (1/4) = 1/24 or about 4.17% To calculate that at most two hit is the complement of everybody hits the target. This will be calculate by 1 - P (All hit). P (All hit) = (1/2) (2/3) (3/4) = 1/4. 1 - 1/4 = 3/4 The probability that at most two hit the target is 3/4 or 75%. Find Math textbook solutions? Webb10 jan. 2024 · The probability that a man will hit a target in shooting practise is `0.3`. If he shoots 10 times, the probability that he hits the target , is. asked Jan 10, 2024 in …

probability that one of them hit the target [closed]

Webb17 mars 2024 · The probability that three men hit a target are \[0.3\], \[0.5\], and \[0.4\] respectively. Each man fires once at the target. (Assume that the three events that each … Webb21 maj 2002 · The probabilities that three men hit a target are 1/6, 1/4, and 1/3, respectively. Each shoots once at the traget. If only one of them hits the traget, find the … imperial blue whisky price philippines

Two men hit at a target with probabilities 1/2 and 1/3 respective

WebbThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: The probability of a man hitting a target is … WebbExpert Answer 100% (1 rating) Transcribed image text: Situation: The probabilities that three men hit a target are 1/6, 1/4 and 1/3, respectively. Each shoots once at the target. Find the probability that exactly one of them hits the target. WebbThe probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 2 will miss the target. Advertisement Remove all ads Solution Let X = number of bombs hitting the target. p = probability that bomb will hit the target ∴ p = 0.8 = 8 10 = 4 5 ∴ q = 1 - p = 1 - 4 5 = 1 5 Given: n = 10 ∴ X ~ B ( 10, 4 5) imperial blvd sugar land tx